Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)%0D%0AResponses%0D%0A%0D%0A12x+210=15x+180%0D%0A12 x plus 210 equals 15 x plus 180%0D%0A%0D%0A12x−210=15x−180%0D%0A12 x minus 210 equals 15 x minus 180%0D%0A%0D%0A210−12x=180−15x%0D%0A210 minus 12 x equals 180 minus 15 x%0D%0A%0D%0A12x+180=15x+210%0D%0A12 x plus 180 equals 15 x plus 210
1 answer
12x + 210 = 15x + 180