Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)
5 answers
180 + 15x = 210 + 12x
Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)
180 + 15x = 210 + 12x
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Apologies for the mistake.
Let's use x as the number of minutes it takes for the machines to fill the same number of cans.
For the first machine, the number of cans filled is given by 180 + 15x (180 cans filled initially and then 15 cans per minute).
For the second machine, the number of cans filled is given by 210 + 12x (210 cans filled initially and then 12 cans per minute).
To find when the two machines will have filled the same number of cans, we can set these two expressions equal to each other:
180 + 15x = 210 + 12x
Let's use x as the number of minutes it takes for the machines to fill the same number of cans.
For the first machine, the number of cans filled is given by 180 + 15x (180 cans filled initially and then 15 cans per minute).
For the second machine, the number of cans filled is given by 210 + 12x (210 cans filled initially and then 12 cans per minute).
To find when the two machines will have filled the same number of cans, we can set these two expressions equal to each other:
180 + 15x = 210 + 12x
1 answer