two machines at a factory are filling can of soup. one machine has filled 92 cans of soup. it fills can at a rate of 16 cans per minute. the second machine has filled 104 cans of soup. it fills cans at a rate of 13 cans per minute. write and solve an equation to show when the two machines will have filled the same number of cans of soup.

a. 92 + 16x = 104 + 13x ; x = 6
b. 92 - 16x = 104 - 13x ; x = -4
c. 104 + 16x = 92 + 13x ; x = 4
d. 92 + 16x = 104 + 13x ; x = 4

1 answer

The correct equation is:

92 + 16x = 104 + 13x

Solving for x:

16x - 13x = 104 - 92
3x = 12
x = 4

Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.

The correct answer is:

c. 104 + 16x = 92 + 13x ; x = 4