Two machines at a factor of filling cans of soup one machine has filled 92 cans of soup it feels at a rate of 16 cans per minute the second machine has failed 104 cans of soup it fails cans at a rate of 13 cans per minute.Right and solve an equation to show when the two machines will have filled the same number of cans of soup

keyword: EQUATION.

3 answers

Let x be the number of minutes it takes for the two machines to have filled the same number of cans of soup.

Machine 1: 16 cans/minute
Machine 2: 13 cans/minute

The equation can be set up as:
92 + 16x = 104 + 13x

Solve for x:
16x - 13x = 104 - 92
3x = 12
x = 4

Therefore, it will take 4 minutes for the two machines to have filled the same number of cans of soup.
write a damn equation!!!!!!!!!!!!!!!!!!!!!
Let x be the number of minutes it takes for the two machines to have filled the same number of cans of soup.

Machine 1:
Cans filled = 92 + 16x

Machine 2:
Cans filled = 104 + 13x

To find when the two machines will have filled the same number of cans of soup, set the two equations equal to each other:

92 + 16x = 104 + 13x

Solving this equation will give you the answer for when the two machines will have filled the same number of cans of soup.
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