Let "t" be the number of minutes it takes for the two machines to fill the same number of cans of soup.
The first machine fills cans at a rate of 16 cans per minute, so the number of cans it fills in "t" minutes is 16t.
The second machine fills cans at a rate of 13 cans per minute, so the number of cans it fills in "t" minutes is 13t.
We can set up the equation:
16t = 13t + (104 - 92) [The difference in the number of cans filled by the second machine is (104 - 92)]
Simplifying the equation, we get:
16t - 13t = 12
3t = 12
t = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.
Two machines at a factor of filling cans of soup one machine has filled 92 cans of soup it feels at a rate of 16 cans per minute the second machine has failed 104 cans of soup it fails cans at a rate of 13 cans per minute.Right and solve an equation to show when the two machines will have filled the same number of cans of soup
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