10/10 = 1 beat/s
10/5 = 2 beats/s
255 + 1 = 256
258 - 2 = 256
so 256
two loudspeakers are set to produce waves at 255Hz and 258Hz respectively. a tuning fork of unknown frequency is sounded together with each speaker in turn. with the 255Hz speaker it produces 10 beats in 10second and with the 258Hz speaker it produces 10beats in 5second. what is the frequency of the tuning fork?
2 answers
Some historical trivia: 256 Hz used to be middle C, but with equal-tempered tuning based upon A = 440 Hz, middle C has been changed to 262 Hz.
1 answer