Two loudspeakers are 2.54 m apart. A person stands 3.04 m from one speaker and 3.50 m from the other. What is the lowest frequency at which destructive interference (sound cancellation) will occur at this point?

Answer 1

distances have to be one half wavelength apart.

3.04-3.50=1/2 lambda

lambda= .92meter check that, so

f= velocitysound/.92