Asked by Student in Need
Two loudspeakers are 2.54 m apart. A person stands 3.04 m from one speaker and 3.50 m from the other. What is the lowest frequency at which destructive interference (sound cancellation) will occur at this point?
Answers
Answered by
bobpursley
distances have to be one half wavelength apart.
3.04-3.50=1/2 lambda
lambda= .92meter check that, so
f= velocitysound/.92
3.04-3.50=1/2 lambda
lambda= .92meter check that, so
f= velocitysound/.92
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