According to my sketch:
tan46°10' = 7/AP
AP = 7/ tan46°10' = ....
sin46°10' = 7/BP
BP = 7/sin46°10' = ....
two lighthouses are situated such that B is 7 km directly east of lighthouse A. A ship at point P observes that A is due north and that the bearing of B is 46°10'. How far is the ship from A and B ?
3 answers
how do you sketch this kind of problem?, that's the reason why i'm having trouble with this ..
first thing, of course, is to draw line AB. B is east of A, so it's horizontal.
A is due north of P, so draw a line south from A and put P somewhere on it.
You can estimate angles, at least to some degree :-) so make PB at about 45 degrees.
A is due north of P, so draw a line south from A and put P somewhere on it.
You can estimate angles, at least to some degree :-) so make PB at about 45 degrees.