Two jets leave an airport at the same time, flying in opposite directions. The first jet is traveling at three hundred seventy-seven mph and the other at two hundred seventy-five mph. How long will it take for the jets to be 9128 miles apart?

Answer 1

To find the time it takes for the jets to be 9128 miles apart, we need to use the formula:

distance = rate x time

Let's call the time it takes for the jets to be 9128 miles apart "t". Then we can write two separate equations for each jet:

distance traveled by first jet = rate of first jet x time
distance traveled by second jet = rate of second jet x time

Since the jets are flying in opposite directions, their distances are adding up to the total distance of 9128 miles:

distance traveled by first jet + distance traveled by second jet = 9128

Substituting in the given rates and our variable for time, we get:

377t + 275t = 9128

Simplifying and solving for t, we get:

652t = 9128

t = 14

Therefore, it will take 14 hours for the jets to be 9128 miles apart.