Two isosceles triangles have perimeters of 8 and 15 centimeters, respectively. They have the same base length, but the legs (the non base sides) of the larger triangle are twice as long as the legs of the smaller triangle. For each triangle, what is the length of a leg?

Answer 1

small: 8 = b+2x
large: 15 = b+2y
y=2x

b+y=8
b+2y=15
y=7
b=1
x=7/2

small: 7/2 + 7/2 + 1 = 8
large: 7+7+1=15