First find the tension in the thread:
Tcos18 = mg
Now the charge
Tsin18 = kq^2/r
Find r from geometry
.25 sin18 = r/2
Two identical, small balls are suspended by separate 0.25m threads that are attached to a common point on the ceiling. Each ball has a mass of 8.0 x 10^-4 kg. Initially the balls are uncharged and hang straight down. They are then given identical positive charges and, as a result, spread apart with an angle of 36 degrees between the threads.
A) Determine the charge on each ball
B) Determine the tension in the threads
5 answers
when I find the tension in the thread, do I plug in the mass of the ball in the equation?
Also,to find the charge, wouldn't the angle be 36 degrees so why would I use .25sin18 rather than .25sin36?
Thirdly, for the part about kq^2/r... what would be the q value and would the r value be 0.25 or would it be half of 0.25?
Please answer all my questions. I don't understand this problem!
Thank you!!!
Also,to find the charge, wouldn't the angle be 36 degrees so why would I use .25sin18 rather than .25sin36?
Thirdly, for the part about kq^2/r... what would be the q value and would the r value be 0.25 or would it be half of 0.25?
Please answer all my questions. I don't understand this problem!
Thank you!!!
half of 36 is 18 degrees, so u would use 18 degrees rather than 36.
CAN SOMEONE PLEASE EXPLAIN WHAT I WOULD PLUG IN FOR THE MASS (IN ORDER TO FIND THE TENSION) AND ALSO WHAT THE "Q" VALUE WOULD BE TO FIND THE CHARGE!!!
AM I SOLVING FOR THE "Q" VALUE?
0 answers