power = V^2/Req = 9.8 = 26^2/Req
so
Req = 69 ohms
so R = 2 Req = 138 Ohms
new Req:
1/Req = 1/138 + 1/276
Req = 92 Ohms
power = 26^2/92 = 7.35 Watts
Two identical resistors are connected in parallel across a 26-V battery, which supplies them with a total power of 9.8 W. While the battery is still connected, one of the resistors is heated so that its resistance doubles. The resistance of the other resistor remains unchanged.
Answer:
V^2/watts = ohms
V^2/ohms + V^2/2(ohms) = W
1 answer
1 answer