Pellet A:
V = Vo + g*Tr
Tr = -Vo/g = -27.3/-9.8 = 2.79 s. = Rise
time.
Tf1 = Tr = 2.79 s. = Time to Fall back to the edge of the cliff.
Tf2 = Fall time from edge of cliff to
gnd.
Ta = Tr + Tf1 + Tf2 = 2.79 + 2.79 + Tf2 = 5.57 + Tf2. = Time in air, pellet A
Pellet B:
Tb = Tf = Tf2: Same initial velocity and distance.
(5.57+Tf2) - Tf2 = 5.57 s. After pellet
B hits the gnd.
Two identical pellet guns are fired simultaneously from the edge of a cliff. These guns impart an initial speed of 27.3 m/s to each pellet. Gun A is fired straight upward, with the pellet going up and then falling back down, eventually hitting the ground beneath the cliff. Gun B is fired straight downward. In the absence of air resistance, how long after pellet B hits the ground does pellet A hit the ground?
1 answer