The repulsive force between two charges is given by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Therefore, for the first scenario with two pith balls each with +3nC of charge that are 10 cm apart, the force would be:
F1 = k * (3e-9)^2 / (0.1)^2
And for the second scenario with two pith balls each with +2nC of charge that are 6 cm apart, the force would be:
F2 = k * (2e-9)^2 / (0.06)^2
Where k is Coulomb's constant.
Comparing the two forces, we find that F1 is stronger than F2. Thus, the two pith balls each with +3nC of excess charge that are 10 cm apart feel a stronger repulsive force.
Two identical metallic spheres, labeled A and B, carry excess charges of +1µC (sphere A) and +3µC (sphere b). What feels a stronger repuslive force ... two pith balls each with +3nC of excess charge that are 10 cm apart, or two pith balls each with +2nC of charge that are 6 cm apart?
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