Two identical boxcars (m = 14866 kg) are traveling along the same track but in opposite directions. Both boxcars have a speed of 5 m/s. If the cars collide and couple together, what will be the final speed of the pair?

Answer 1

M1V1 + M2V2 = M1V + M2V.
14866*5-14866*5 = 14866V+14866V,
V = 0.

Answer 2

(M=18913 kg)6 m/s

Answer 3

850kg 30m/s