nope. consider the fraction of the job done in one hour:
1/3 + 1/b = 1/2
In this case you got lucky, since indeed 1/3 + 1/6 = 1/2.
Two hoses together fill a pool in 2 h. If only hose A is used, the pool fills in 3 h. How long would it take to fill the pool if only hose B were used?
I multiplied 3 and 2 and got 6 hours.
Is this a valid method?
Thanks
2 answers
Thanks!