(a) ma=F1+F2 =0
F2=F1 = 27.56 N
(b)ma=F1+F2
1.11•(-9.3) = 27.56 +F2
F2= -37.883 N
two horizontal forces F1 and F2, acting on an object of mass 1.11kg. The magnitude of F1 is 27.56N. The object moves strictly along the horizontal x-axis, which we choose as positive to the right. Find the magnitude of F2 if the object has a horizontal acceleration of 8.4m/s^2.
b). What is the magnitude of F2 if the object has a horizontal acceleration of 0m/s^2?
c). What is the magnitude of F2 if the object has a horizontal acceleration of -9.30m/s^2?
2 answers
for b, switch the negative to positive. F2 is in the negative direction so the negative on your answer and the negative on F2 cancel