Two hockey players strike a puck of mass 0.168 kg with their sticks simultaneously, exerting forces of 1.16 103 N, directed west, and 9.90 102 N, directed 30.0° east of north. Find the instantaneous acceleration of the puck.

1 answer

30o E. of N. = 60o CCW.

Fr = -1160 + 990[60].
Fr = -1160 + 990*Cos60+990*sin60,
Fr = -1160 + 495+857.4i,
Fr = -665 + 857.4i = 1085N[-52.2] = 1085N[127.8o] = Resultant force.

Fr = M*a = 1085[127.8o].
0.168a = 1085[127.8,
a = 6458 m/s^2[127.8o].