Nuts to this, it makes no sense.
What does "cost their past" mean?
If you mean
group A in favor: 128
group A opposed: 32
group B in favor: 96
group B opposed: 48
Now if all those infavor (128+96), if one is selected, Pr(A)=128/(128+96)
If a student is chosen at random,
Pr(against)=totalagainst/total students
= (32+48)/(128+32+96+48)
Two group of male students cost their past on a particular proposal.the result are as follows: Group infavour against A 128 32 B 96 48 <a> if a student in favour of proposal is selected for a post. What is the probability that he is from group A ? if a student is chosen at random, what is the probability that he is against proposal.
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I am also confused by what "in favour against" means.
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