Two gases A and B are separated by a partition within a box. Gas A contract having 730j of work done on it . 140 of energy are transfered to gas B from A due to a temperature difference. By how much does the internal energy of A change?

1 answer

To solve this problem, we need to consider the first law of thermodynamics:

ΔU = Q - W

Where ΔU is the change in internal energy, Q is the heat transferred, and W is the work done on the system.

In this case, gas A contracts and has 730 J of work done on it, so W = 730 J. Additionally, 140 J of energy are transferred from gas A to gas B due to a temperature difference, so Q = -140 J (negative because energy is transferred from A to B).

Plugging these values into the first law of thermodynamics equation, we have:

ΔU = -140 J - 730 J

ΔU = -870 J

Therefore, the internal energy of gas A decreases by 870 J.