a) the vertical asymptote equation is
x = -1 , you had just -1 , but it asked for the equation.
your horizontal asymptote is correct
g(x) = x-6 is a straight line, with no asymptotes.
b), yes , find the roots ...
3/(x+1) = x-6
x^2 -5x - 6 = 3
x^2 - 5x - 9 = 0
does not factor, so let's use the formula
x = (5 ± √61)/2
= appr 6.405 or -1.405
two functions are defined as follows: f(x)=3/x+1 and g(x)=x-6
a) Write the equations of the vertical and horizonal asymptotes of f.
b) Determine the coordinates of the points where f(x) = g(x)
Thank you so much for huge help
Is ti correct please?
answer for a) vertical asympt.: -1
horizontal asympt.: y = 0
gor g is vertical asympt.: 6
horizon asympt: -6
b) x^2-5x-9 = 0
now I need to find two roots, right?
Thank you so much for help, I have no idea, please help me:)))
3 answers
Thank you so much . a)Equation is x=-1vertical asympt. Is it correct please?
yes, that is what I had stated in my reply.