Two forces of magnetude 6N and 10N act on a particle.their resultant is of magnitude 12N.find the angle between the two forces.
2 answers
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Make a rough sketch of the two vectors of 6N and 10N, completing a parallelogram so that the major diagonal is 12N
So looking at the triangle with sides 10,6, and 12
we can find the obtuse angle Ø by
12^2 = 6^2 + 10^2 - 2(6)(12)cosØ
144 cosØ = -8
cosØ = -1/18
Ø = appr 93.18°
then we can find the angle opposite side of length 6
sinA/6 = sin93.18/12
sinA = .499..
angle A = 29.95
leaving 56.87° for the third angle
so the angle between them is 56.87° + 29.95°
or 86.82°
So looking at the triangle with sides 10,6, and 12
we can find the obtuse angle Ø by
12^2 = 6^2 + 10^2 - 2(6)(12)cosØ
144 cosØ = -8
cosØ = -1/18
Ø = appr 93.18°
then we can find the angle opposite side of length 6
sinA/6 = sin93.18/12
sinA = .499..
angle A = 29.95
leaving 56.87° for the third angle
so the angle between them is 56.87° + 29.95°
or 86.82°
2 answers