Two forces F1and F2 on a particle. F1 has magnitude 5N and in direction 030°,and F2 has magnitude 8N and in direction 090°.find the magnitude and direction of their resultant.
2 answers
i can't solve it so i need your help
F1 = 5 sin 30 East + 5 cos 30 North = 2.5 E + 4.33 N
F2 = 8 sin 90 East + 8 cos 90 North = 8.0 E + 0.00 N
add
F = 10.5 E + 4.33 N
|F| = sqrt (10.5^2 + 4.33^2) = sqrt (110.25 + 18.75) =sqrt (129)
= 11.4 Newtons
tan direction = E/N = 10.5 / 4.33 = 2.42
direction = 67.6 degrees compass(clockwise from North)
F2 = 8 sin 90 East + 8 cos 90 North = 8.0 E + 0.00 N
add
F = 10.5 E + 4.33 N
|F| = sqrt (10.5^2 + 4.33^2) = sqrt (110.25 + 18.75) =sqrt (129)
= 11.4 Newtons
tan direction = E/N = 10.5 / 4.33 = 2.42
direction = 67.6 degrees compass(clockwise from North)