How much of F1 is in the +x direction?
F1x = -8 cos 56
How much of F2 is in the +x direction?
F2x = -5 cos 52.9
So how much total in the +x direction?
Fx = F1x+F2x = -8cos56-5cos52.9
How much of F1 is in the +y direction?
F1y = +8 sin 56
How much of F2 is in the +y direction?
F2y = -5 sin 52.9
How much total is in the +y direction?
Fy = +8sin56-5sin52.9
then
|F| = sqrt(Fx^2+Fy^2)
Two forces,F1 and F2, act at a point. F1 has a magnitude of 8.00 N and is directed at an angle of 56.0 degrees above the negative x axis in the second quadrant. F2 has a magnitude of 5.00 N and is directed at an angle of 52.9 degrees below the negative x axis in the third quadrant.
-What is the x component of the resultant force?
-What is the y component of the resultant force?
-What is the magnitude of the resultant force?
Im confused.
1 answer