ma=F1+F2
F2=ma-F1=2.8•2.5 -12 =-5 N (in -x-direction)
Two forces are the only forces acting on a
2.8 kg object which moves with an accelera-
tion of 2.5 m/s2 in the positive y direction.
One of the forces acts in the positive x direc-
tion and has a magnitude of 12 N.
What is the magnitude of the other force
f2?
Answer in units
2 answers
F1+F2 = M*a = 2.8*2.5i = 7i.
12+F2 = 7i, F2 =-12 + 7i=13.9 N[30.3o] N. of W.
12+F2 = 7i, F2 =-12 + 7i=13.9 N[30.3o] N. of W.