Two forces are exerted on a hockey puck which initially stopped on frictionless ice. Force 1 is exerted in the positive x direction with magnitude of 10 N and Force 2 is exerted in the positive Y direction with magnitude 4 N. The hockey puck has a mass of 0.5 kg. What is the magnitude and direction of the resulting acceleration?

Answer 1

sqrt (100 + 16) = sqrt 116
= srt (4*29) = 2 sqrt(29)

tan angle above x axis = 4/10

|a| = (1/.5) *2 sqrt 29
= 4 sqrt 29 at same tan^-1(.4)