Two forces are applied to a car in an effort to move it, F1 is 400N and F2 is 450N, F1 is 30 degrees in the upper right and F2 is 10 degrees in the upper left)

Question

(a) What is the resultant vector of these two forces?
(b) If the car has a mass of 3 000 kg, what acceleration does it have? Ignore friction.

Answer 1

All angles are = measured CCW from +x-axis.
a. Fr = 400 N.[30o] + 450N.[170] = Resultant force.
X = 400*Cos30+450*Cos170 = -97 N.
Y = 400*sin30+450*sin170 = 278 N.
Fr = -97 + 278i = 294N.[-71o] = 294N.[71o] S. of E. = 294N.[289o] CCW.

b. Fr = M*a = 294.
3000*a = 294,
a =