a. Fr = 328N[35o] + 464N[13o]
X = 328*Cos35 + 464*Cos13 = 721 N.
Y = 328*sin35 + 464*sin13 = 293 N.
Fr^2 = X^2 + Y^2 = 721^2 + 293^2 = 605,690.
Fr = 778 N. = Resultant force.
b. a = F/m = 778/2950 = 0.264
Two forces are applied to a car in an effort to accelerate it, as shown below. The first force, F1 = 328 N, is applied at an angle α = 35° to the forward dashed line. The second force, F2 = 464 N, is applied at an angle β = 13° to the forward dashed line.
(a) What is the resultant of these two forces?
(b) If the car has a mass of 2950 kg, what acceleration does it have? (Disregard friction.)
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1 answer