40 S = <0,-40>
70 N30ºW = <-35,60.6>
add them up, then convert back to compass directions.
Two forces are applied to a box on a frictionless surface. One force is 40 N [S]. The second force is 70 N [N30ºW]. What is the overall net force?
a) 40.6 N [S59.5ºE]
b) 110 N
c) 40.6 N [N59.5ºW]
d) 40.6 N [S30.5ºW]
1 answer
1 answer