To find the horizontal acceleration of the block, we first need to find the net force acting on the block in the horizontal direction.
The two forces acting on the block in the horizontal direction are F1 and F2.
F1 = 6 N
F2 = 4 N
The net force Fnet in the horizontal direction is the vector sum of F1 and F2:
Fnet = F1 - F2
Fnet = 6 N - 4 N
Fnet = 2 N
Now, we use Newton's second law to find the acceleration of the block:
Fnet = ma
2 N = 4.5 kg * a
a = 2 N / 4.5 kg
a = 0.444 m/s²
Therefore, the magnitude of the horizontal acceleration of the block is 0.444 m/s².
Two forces act on a 4.5 kg block resting on a frictionless surface as shown in the Figure. What is the magnitude of the horizontal acceleration of the block?
3.2 m/s2
1.8 m/s2
1.8 m/s2
1.2 m/s?
1 answer