To determine which fertilizer is generally more effective based on the potato weights provided, we need to calculate the mean and median for each set of data.
Fertilizer A weights: 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Calculating the mean for Fertilizer A:
Mean = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10
Mean = 21.2 kg
Calculating the median for Fertilizer A:
First, sort the values:
16, 17, 18, 19, 19, 20, 21, 22, 23, 27
Median = (19 + 20) / 2 = 19.5 kg
Fertilizer B weights: 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
Calculating the mean for Fertilizer B:
Mean = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10
Mean = 23.2 kg
Calculating the median for Fertilizer B:
First, sort the values:
18, 19, 20, 21, 21, 24, 25, 27, 28, 29
Median = (21 + 24) / 2 = 22.5 kg
Summary of Results:
- Fertilizer A: Mean = 21.2 kg, Median = 19.5 kg
- Fertilizer B: Mean = 23.2 kg, Median = 22.5 kg
Given that both the mean and the median of the weights of the potatoes treated with Fertilizer B are higher than those for Fertilizer A, we can conclude that:
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
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