To determine which fertilizer is generally more effective, we can compare the mean and median weights of the potatoes treated with each fertilizer.
Fertilizer A: Mean = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10 = 20.2
Median = the middle value when the weights are arranged in ascending order = 20
Fertilizer B: Mean = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10 = 23.2
Median = the middle value when the weights are arranged in ascending order = 21
From the calculations above, we can see that the mean and median weights for the potatoes treated with Fertilizer B are higher than those treated with Fertilizer A. Therefore, the answer is: Fertilizer B is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
Two fertilizers are applied to randomly selected potato plants. After several weeks, the potatoes are weighed. The weights in kilograms are as follows. Which fertilizer is generally more effective?
Fertilizer A: 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Fertilizer B: 28, 19, 18, 21, 24, 20, 25, 27, 29, 21 (1 point)
• Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
• Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
• Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same.
• Fertilizer A is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
1 answer
1 answer