Two fertilizers are applied to randomly selected potato plants. After several weeks, the potatoes are weighed. The weights in kilograms are as follows. Which fertilizer is generally more effective?
Fertilizer A: 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Fertilizer B: 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
(1 point)
Responses
Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
Fertilizer A is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
Fertilizer A is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same.
Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same.
1 answer
For Fertilizer A, the mean weight can be calculated by adding up all the weights and dividing by the number of potatoes:
Mean weight of Fertilizer A = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10 = 202 / 10 = 20.2 kg
To calculate the median weight for Fertilizer A, we need to arrange the weights in ascending order:
16, 17, 18, 19, 19, 20, 21, 22, 23, 27
Since there are an even number of weights, the median is the average of the two middle values: (19 + 20) / 2 = 19.5 kg
For Fertilizer B, the mean weight can be calculated in the same way:
Mean weight of Fertilizer B = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10 = 232 / 10 = 23.2 kg
Again, we need to arrange the weights in ascending order to calculate the median for Fertilizer B:
18, 19, 20, 21, 21, 24, 25, 27, 28, 29
The two middle values are 21 and 24, so the median is (21 + 24) / 2 = 22.5 kg
From the calculations, it can be observed that the mean weight for Fertilizer B (23.2 kg) is higher than the mean weight for Fertilizer A (20.2 kg). Similarly, the median weight for Fertilizer B (22.5 kg) is higher than the median weight for Fertilizer A (19.5 kg).
Therefore, we can conclude that Fertilizer B is generally more effective, as the average and middle weights of the potatoes treated with it are higher.