Two families visited an amusement park. The first family bought 4 hot dogs and 6 bottles of waters, which totaled $22. The second family bought 8 hot dogs and 3 bottles of waters, which totaled $35. How much did one hot dog cost?

Answer 1

Let's use "h" to represent the cost of one hot dog.
And let's use "w" to represent the cost of one bottle of water.

From the problem, we know:
4h + 6w = 22 (equation 1)
8h + 3w = 35 (equation 2)

We want to find the value of "h", so let's solve for "w" in equation 1:
6w = 22 - 4h
w = (22 - 4h)/6
w = (11 - 2h)/3 (divided both sides by 2)

Now we can substitute this expression for "w" into equation 2:
8h + 3(11 - 2h)/3 = 35
8h + 11 - 2h = 35
6h = 24
h = 4

Therefore, one hot dog costs $4.