Two fair number cubes are tossed and the numbers added. Determine the probability that the sum is a number divisible by 3. Write your response as a fraction.(1 point)

Answer 1

There are a total of 36 possible outcomes when two fair number cubes are tossed (6 outcomes on the first cube and 6 outcomes on the second cube).

To determine the probability that the sum is a number divisible by 3, we need to find all the sums that are divisible by 3. These sums would be 3, 6, 9, and 12.

The number of ways to get a sum of 3: (1, 2) and (2, 1) = 2 ways
The number of ways to get a sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), and (5, 1) = 5 ways
The number of ways to get a sum of 9: (3, 6), (4, 5), and (5, 4) = 3 ways
The number of ways to get a sum of 12: (6, 6) = 1 way

Therefore, the total number of favorable outcomes is 2+5+3+1 = 11.

The probability that the sum is a number divisible by 3 is 11/36.

So, the probability is 11/36.