Let m be the smaller mass and v be the velocity of that mass. Let M be the larger mass and V be its velocity.
Because the energies are equal,
m v^2 = M V^2
(mv)^2/m = (MV)^2/M
mv/(MV) = sqrt (m/M) < 1
(since m/M < 1)
Therefore the smaller mass also has less momentum.
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You left out the dimensions of the mass of the baseball. I assume it is kg
Momentum magnitude is mass x velocity. You should know that. Do the calculation. Don't forget the units, which should be kg m/s
Your last two questions require you to apply the law of conservation of momentum
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