There are 6 ways to get a sum of 7 and 1 way to get a sum of 12
So there are 7 ways for your event to happen
Prob(event) = 7/36
prob(not the event) = 29/36
odds in favour of getting a sum of 7 or a sum of 12
= (7/36) : (29/36)
= 7 : 29
Two dice are rolled. Find the odds that the score on the dice is either 7 or 12.
A) 7 : 29
B) 1 : 5
C) 1 : 1
D) 19 : 17
I am so lost it isn't funny. I do not know how to figure this out.
1 answer