d1 = Vo*t + (g/2)t^2. Vo = 0.
d1 = (g/2)t^2.
d2 = (g/2)(t-1)^2.
d1 = d2 + 10.
(g/2)t^2 = (g/2)(t-1)^2 + 10,
4.9t^2 = 4.9(t-1)^2 + 10,
4.9t^2 - 4.9(t-1)^2 = 10,
divide both sides by 4.9:
t^2 - (t-1)^2 = 2.04,
t^2 - (t^2-2t+1) = 2.04,
t^2 - t^2 + 2t - 1 = 2.04,
2t - 1 = 2.04,
2t = 3.04,
t = 1.52s.
Two Diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10m apart?
Please help, I am very confused with this question, I have completed all other but I am unsure about how to answer this. Any help is greatly appreciated!
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