Two containers to hold water side-by-side both in shape of a cylinder contain container a has a diameter of 16 feet and a height 19 feet container B has a diameter of 26 feet and a height of 13 feet container is full of water and the water is pumped into container into container is empty after the pumping is complete. What is the volume of the empty portion of container B to the nearest 10th of a cubic foot

1 answer

To find the volume of the empty portion of container B, we first need to calculate the volume of water that was transferred from container A to container B.

The volume of container A can be calculated using the formula for the volume of a cylinder:
V = πr^2h
where r is the radius of the cylinder and h is the height of the cylinder.

For container A:
r = 16 feet / 2 = 8 feet
h = 19 feet

V(A) = π(8^2)(19)
V(A) = 3015.93 cubic feet

Now, let's calculate the volume of container B:
r = 26 feet / 2 = 13 feet
h = 13 feet

V(B) = π(13^2)(13)
V(B) = 6595.95 cubic feet

Since the water transferred from container A completely fills container B, the volume of the empty portion of container B can be found by subtracting the volume of the water from the volume of the container:
Empty Volume (B) = V(B) - V(A)
Empty Volume (B) = 6595.95 - 3015.93
Empty Volume (B) = 3571.02 cubic feet

Therefore, the volume of the empty portion of container B is approximately 3571.0 cubic feet to the nearest 10th of a cubic foot.