Two containers designed to hold water are side by side in a shape of a cylinder. Container A has a diameter of 22 feet and a height of 19 feet. Container B has a diameter of 28 feet and a height of 18 feet. Container A is full of water and is pumped into container B until Container A is empty. After the pumping is complete what is the volume of the empty portion of Container B to the nearest tenth of a cubic foot?

Answer 1

To find the volume of the empty portion of Container B after pumping water from Container A into it, we need to first calculate the initial volume of water in Container A and then subtract it from the total volume of Container B.

First, let's find the volume of water in Container A:
Radius of Container A = Diameter / 2 = 22 / 2 = 11 feet
Volume of water in Container A = πr^2h = π(11)^2(19) = 7542.584 cubic feet

Now, let's find the total volume of Container B:
Radius of Container B = Diameter / 2 = 28 / 2 = 14 feet
Volume of Container B = πr^2h = π(14)^2(18) = 9959.93 cubic feet

Finally, we can find the volume of the empty portion of Container B:
Empty volume of Container B = Total volume of Container B - Volume of water in Container A
Empty volume of Container B = 9959.93 - 7542.584 ≈ 2417.35 cubic feet

Therefore, the volume of the empty portion of Container B after pumping water from Container A into it is approximately 2417.4 cubic feet.