Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 4 feet and a height of 9 feet. Container B has a radius of 3 feet and a height of 11 feet. Container A is full of water and the water is pumped into Container B until Container B is completely full.

After the pumping is complete, what is the volume of water remaining in Container A, to the nearest tenth of a cubic foot?

1 answer

To find the volume of water remaining in Container A, we first need to find the volume of both containers.

The volume of a cylinder is calculated using the formula: V = πr^2h, where r is the radius and h is the height of the cylinder.

For Container A:
V_A = π(4)^2(9) = 144π cubic feet

For Container B:
V_B = π(3)^2(11) = 99π cubic feet

After pumping the water from Container A to Container B, the remaining volume in Container A is:
Remaining Volume = V_A - V_B = 144π - 99π = 45π cubic feet

Now, to find the volume of water remaining in Container A to the nearest tenth of a cubic foot, we can calculate:
Remaining Volume ≈ 45π = 141.4 cubic feet

Therefore, the volume of water remaining in Container A is approximately 141.4 cubic feet.