Asked by Alli

Two consecutive odd integers have a sum that is, at most, 36. What is the greatest value the larger number could have?
Answered by oobleck
if x is the larger, x-2 is the smaller, since odd number differ by 2
So,
x-2 + x <= 36
solve for x
Answered by henry2,
x + ( x+2) <= 36
X <= 17.
x+2 <= 19.
Therefore, x+2 = 19, max.
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