Two consecutive numbers are such that five times the smaller one exceeds twice the greater by 16. Find the numbers

Answer 1

let the numbers be x and x+1. Then we know that
x = 2(x+1) + 16

Answer 2

I can't really understand the answer

Answer 3

I need the answer

Answer 4

Let the numbers be a, a+1
5a = 2(a+1)+16
5a = 2a+ 2+16
5a-2a = 18
3a/3 = 18/3
a = 6
= 6 and 7