Substitute 1.5i for Z in the equation.
W = (1 + 1.5i)/(1 - 1.5i)
This can be simplied by multiplying numerator and denominator by 1 + 1.5i. It gets rid of the complex deniminator. W = (1 + 1.5i)^2/(1 + 1.5)^2)
= (1/3.25)* (1 + 3i -2.25)
= (4/13)(-1.25 + 3i)
= -5/13 + 12i/13
two complex numbers Z and W are related by the formula
W=(Z+1)/(1-Z)
what is W if Z=1.5i?
thanks for the help!
4 answers
ah!!i was so dumb! i was trying to multiplying numerator and denominator by 1+Z,of course it didn't work out...haha...
thankyou !!!!
thankyou !!!!
Anne, you were not so dumb at all!
I solved the above question the same way by multiplying top and bottom by 1+Z.
Whether you substitute first and then multiply like drwls did, or multiply first and then substitute does not matter, you should get the same result.
I had (3i-1.25)/(13/4)
= (12i-5)/13 which is also drwls' answer
Check your work, you must have made an error.
I solved the above question the same way by multiplying top and bottom by 1+Z.
Whether you substitute first and then multiply like drwls did, or multiply first and then substitute does not matter, you should get the same result.
I had (3i-1.25)/(13/4)
= (12i-5)/13 which is also drwls' answer
Check your work, you must have made an error.
yeah...i did made an error...
3.35 instead of 3.25...haha.
thx guys!
3.35 instead of 3.25...haha.
thx guys!