you have it exactly backwards.
0.2 is the probability that NO heads showed.
Two coins were tossed 10 times. The result is shown in the table below.
Toss: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
Result: 1)HH, 2)TT, 3)HT, 4)TH, 5)HT, 6)HH, 7) TH, 8)TT, 9) TH, 10) HT
What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
A 0.8
B: 0.2*
C: 0.6
9 answers
Experimental probability means you go with the number of success in the experiment divided by the total number of trials.
Here success is defined as at least one of the coins landed on heads, i.e. includes HH, HT, TH.
Count the total number of the above outcomes and divide by 10 to get the experimental probability.
Hint: the only outcome excluded is TT. Here it is easier to count the number of failures (TT) and subtract from 10 to get the number of successes.
Here success is defined as at least one of the coins landed on heads, i.e. includes HH, HT, TH.
Count the total number of the above outcomes and divide by 10 to get the experimental probability.
Hint: the only outcome excluded is TT. Here it is easier to count the number of failures (TT) and subtract from 10 to get the number of successes.
Oh my god I must be very dumb, I am so lost.
So am I supposed to add up the toss which gives me 55 and divide by 10?
So am I supposed to add up the toss which gives me 55 and divide by 10?
No. There were 10 tosses. 8 of them showed at least one H
So, P = 8/10 = 0.8
So, P = 8/10 = 0.8
Ohhh! I get it, I over thought it. Thank you so much for everyone who helped!
The answer the this specific question was 0.75.
Don't know you're under xx or "help! pls", but this question cannot have an answer of 0.75 because it deals with experimental probability, which bases it on the outcomes of the experiment.
However, the theoretical probability, which is the mathematical answer, is 0.75.
However, the theoretical probability, which is the mathematical answer, is 0.75.
Two coins were tossed 10 times. The results are shown in the table.%0D%0A%0D%0A%0D%0AToss %091%092 %093 %094 %095 %096 %097 %098 %099 %0910 %0D%0AResult%09HH%09TT %09HT %09TH %09HT %09HH %09TH %09TT %09TH %09HT%0D%0A%0D%0AUse the table and information to answer the question.%0D%0A%0D%0A%0D%0A%0D%0A3. What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
The experimental probability of at least one coin landing on heads is the number of successful outcomes (HH, HT, TH) divided by the total number of trials. We can see from the table that out of 10 tosses, only 1 toss resulted in no head (TT), meaning the other 9 tosses had at least one head. Therefore, the experimental probability is 9/10 or 0.9.