Two children sit on opposite sides of a seesaw and the seesaw is balanced. They take turns standing on a bathroom scale, and it reads 75 pounds for each of them. If the children go to the moon and attempt the exact same procedures, what would change? What would stay the same?

Answer 1

On the Moon, the seesaw would still be balanced if the children are sitting on opposite sides, assuming no other variables affect the balancing conditions. Here’s what would change and what would stay the same:

What would change:

1. Weight Measurement: The bathroom scale would read different values on the Moon compared to Earth. Since the Moon's gravitational pull is about 1/6th that of Earth's, each child's weight measured on the scale would read approximately 12.5 pounds (75 pounds x 1/6). This is because weight is the force exerted by gravity on an object.

What would stay the same:

1. Mass: The children's mass would remain the same. Mass is a measure of the amount of matter in an object and does not change regardless of the gravitational force acting on it. Each child still has a mass of about 75 pounds divided by the acceleration due to gravity (approximately 32.2 ft/s² on Earth), which converts to about 11.6 slugs.

2. Balance of the Seesaw: If the children sit in balanced positions (e.g., equal distances from the pivot, assuming they have equal mass as per the original condition), the seesaw system would remain in balance. This is because the seesaw balances based on torque, which is a function of the distance from the pivot point and the force (weight) acting downwards. Each child's force would still create the same torque relative to the seesaw's pivot, given they are the same mass.

In summary, while the weight measurement changes on the Moon due to different gravity, the principles of mass, balance, and torque remain the same, allowing the seesaw to still function correctly.

Answer 2

What is the name of the property that determines whether objects sink or float in water?

Answer 3

The property that determines whether objects sink or float in water is called buoyancy. This is governed by Archimedes' principle, which states that an object submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced by the object. If the buoyant force is greater than the weight of the object, it will float; if it's less, the object will sink. Additionally, the density of the object relative to the density of the fluid plays a crucial role: objects with a density less than that of water will generally float, while those with a greater density will sink.

Answer 4

Does the density of a material depend on the amount of material present?

Answer 5

No, the density of a material does not depend on the amount of material present. Density is defined as the mass of a substance per unit volume, typically expressed in units like grams per cubic centimeter (g/cm³) or kilograms per cubic meter (kg/m³).

The formula for density is:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

For a given material, its density remains constant regardless of how much of the material you have. For example, whether you have a small amount of gold or a large block of gold, the density of gold will remain the same.

However, the total mass and volume will change with the amount of material. As you increase the mass (more material), the volume may also increase, but the ratio that defines density stays consistent for that specific material.

Answer 6

calculate the density of a gold ring that has a mass of 15.83 grams and a volume of 0.82 milliliters. What is the density of the gold ring. (The formula for density is Density= Mass/Volume)

Answer 7

To calculate the density of the gold ring using the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

where the mass is 15.83 grams and the volume is 0.82 milliliters, we can plug in the values:

\[ \text{Density} = \frac{15.83 , \text{grams}}{0.82 , \text{milliliters}} \approx 19.29 , \text{grams per milliliter (g/mL)} \]

So, the density of the gold ring is approximately 19.29 g/mL.

Answer 8

Now, calculate the density of a gold bar that has a mass of 1,000 grams and a volume of 51.8 milliliters. Use the same formula for density.

Answer 9

To calculate the density of the gold bar using the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

we will use the mass of 1,000 grams and the volume of 51.8 milliliters. Plugging in these values gives:

\[ \text{Density} = \frac{1000 , \text{grams}}{51.8 , \text{milliliters}} \approx 19.31 , \text{grams per milliliter (g/mL)} \]

So, the density of the gold bar is approximately 19.31 g/mL.

Answer 10

Is the density of the gold ring and the gold bar the same or different?

Answer 11

To compare the densities of the gold ring and the gold bar:

• The density of the gold ring is approximately 19.29 g/mL.
• The density of the gold bar is approximately 19.31 g/mL.

While both densities are very close, they are not exactly the same. The slight difference can be attributed to factors such as measurement precision, impurities, or variations in the specific alloy of gold used in the two items.

However, in practical terms, both densities are consistent with the typical density of pure gold, which is around 19.32 g/mL, suggesting that both the ring and the bar are likely made of gold or an alloy very close in density to pure gold.