Two children on a seesaw are able to balance perfectly while on Earth. Would they still be balanced if the seesaw was brought to the moon?(1 point)
5 answers
No, the children would not be balanced if the seesaw was brought to the moon. The force of gravity on the moon is only about 1/6th of the force of gravity on Earth. Therefore, the weights of the children would be much less on the moon, causing an imbalance on the seesaw.
Bailee explained that when traveling to the moon, he needs to pack light because the weight of objects on the moon is the same as their weight on Earth. The mass of the objects is what changes when the gravitational pull changes. Is Bailee correct in his explanation?(1 point)
Responses
Bailee is incorrect. Both the mass and weight will stay the same.
Bailee is incorrect. Both the mass and weight will stay the same.
Bailee is incorrect. Both the mass and weight will change.
Bailee is incorrect. Both the mass and weight will change.
Bailee is incorrect. The mass of the objects stay the same but weight will change.
Bailee is incorrect. The mass of the objects stay the same but weight will change.
Bailee is correct. The weight of the objects stay the same but mass will change.
Responses
Bailee is incorrect. Both the mass and weight will stay the same.
Bailee is incorrect. Both the mass and weight will stay the same.
Bailee is incorrect. Both the mass and weight will change.
Bailee is incorrect. Both the mass and weight will change.
Bailee is incorrect. The mass of the objects stay the same but weight will change.
Bailee is incorrect. The mass of the objects stay the same but weight will change.
Bailee is correct. The weight of the objects stay the same but mass will change.
Bailee is incorrect. Both the mass and weight will stay the same.
Which equation describes the mass of an object in relation to its volume and density?(1 point)
Responses
m=VD
m is equal to cap v over cap d
m=DV
m is equal to cap d over cap v
m=D×V
m=D×V
m=D+V
Responses
m=VD
m is equal to cap v over cap d
m=DV
m is equal to cap d over cap v
m=D×V
m=D×V
m=D+V
m=D×V