Two children hang by their hands from the same tree branch. The branch is straight, and grows out from the tree at an angle of 26° above the horizontal. One child, with a mass of 38 kg, is 1.1 m along the branch from the tree trunk. The other child, with a mass of 34 kg, is 2.9 m along the branch from the tree trunk. What is the magnitude of the net torque exerted on the branch by the children? Assume that the axis is located where the branch joins the tree trunk and is perpendicular to the plane formed by the branch and the trunk.

asked by n_sdn

11 years ago

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1 answer

Torque= weight*length*sinAngle

where Angle here is the angle between the tree branch and the vertical weight. (which is 90-26)
figure the two torques, and add.

answered by bobpursley

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Question

Two children hang by their hands from the same tree branch. The branch is straight, and grows out from the tree at an angle of 26° above the horizontal. One child, with a mass of 38 kg, is 1.1 m along the branch from the tree trunk. The other child, with a mass of 34 kg, is 2.9 m along the branch from the tree trunk. What is the magnitude of the net torque exerted on the branch by the children? Assume that the axis is located where the branch joins the tree trunk and is perpendicular to the plane formed by the branch and the trunk.

1 answer

Torque= weight*length*sinAngle

where Angle here is the angle between the tree branch and the vertical weight. (which is 90-26)
figure the two torques, and add.

Ask a New Question or answer this question.

bobpursley · Answer

Torque= weight*length*sinAngle where Angle here is the angle between the tree branch and the vertical weight. (which is 90-26) figure the two torques, and add.