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Two charges attract each other with a force of 16N. What will be the new force if the distance between them is reduced to 1/2 of its original value?

2 answers

the force is inversely proportional to the square of the distance (inverse-square relation)

the new force is 4 times the original

1 / (1/2)² = 1 / (1/4) = 4
Two identical charges repel each other with a force
of 16N. If the distance between the charges is doubled, the force will be?
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