A is at (0,0)
B is at (1,sqrt 3)
C is at (2, 0)
qa = -1*10^-6
qb = +2*10^-6
E at C due to A = K (-1*10^-6)/4 i + 0 j
E at C due to B = K [(+2*10^-6)/4] [cos 60 i - sin 60 j ]
so
Ex at C = 10^-6 K [ -1/4 +2cos60/4]
Ey at C = 10^-6 K [-.25 sin 60]
|E| = sqrt(Ex^2 + Ey^2)
tan angle from x = Ey/Ex
Two charges -1 microcoulumb and 2 microcoulumb are placed at the corner A and B of an equilateral triangle ABC of side 2m. Calculate the electric field at C
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